mjs611
Structural
- Feb 11, 2008
- 17
I am discussing how to find the reactions at each diaphragm over 2, unequal stories. When finding the reactions at each diaphragm, do you analyze as a continuous member or do you use simple span analysis?
i.e. 20 psf wind load; first story height=20', second story height=10'. With simple span the reaction at the top and middle is 20psf*10'/2=100 plf and 20 psf*(10'/2+20'/2)=300 plf. Using continuous beam analysis, the reaction at the top & middle are 25 plf & 412 plf, respectively. It creates a significant difference.
Thanks for your input on what should be an easy question!
i.e. 20 psf wind load; first story height=20', second story height=10'. With simple span the reaction at the top and middle is 20psf*10'/2=100 plf and 20 psf*(10'/2+20'/2)=300 plf. Using continuous beam analysis, the reaction at the top & middle are 25 plf & 412 plf, respectively. It creates a significant difference.
Thanks for your input on what should be an easy question!