CrudeDudeJr
Petroleum
- Jul 16, 2008
- 11
Thanks for taking a minute to try to help.
I am aware that the solubility of salt (NaCl) in water is 26% to 28% depending upon temperature.
But what I would like to know is how FAST the salt will dissolve (at a given temperature). I will need to do the same thing for anhydrous sodium carbonate. The make-up water is 1,500 TDS.
The idea is that a saturated solution can take a long time to create. And I don't need it to be saturated. I am creating stock solutions for a "chemical cocktail" make-up process and I need the solutions to be of consistent quality. The process is outdoors in the central US and temperature is a concern. We can control the residence time but we need to know what it will be so we can plan. Desired residence times might be on the order of 1 hour. We may need to heat the incoming water to be able to get consistent 6% sodium carbonate solutions. I don't know yet what the stock solution will be for sodium chloride but if someone could please point me to RATE data I would certainly be appreciative.
Thanks
Mark
I am aware that the solubility of salt (NaCl) in water is 26% to 28% depending upon temperature.
But what I would like to know is how FAST the salt will dissolve (at a given temperature). I will need to do the same thing for anhydrous sodium carbonate. The make-up water is 1,500 TDS.
The idea is that a saturated solution can take a long time to create. And I don't need it to be saturated. I am creating stock solutions for a "chemical cocktail" make-up process and I need the solutions to be of consistent quality. The process is outdoors in the central US and temperature is a concern. We can control the residence time but we need to know what it will be so we can plan. Desired residence times might be on the order of 1 hour. We may need to heat the incoming water to be able to get consistent 6% sodium carbonate solutions. I don't know yet what the stock solution will be for sodium chloride but if someone could please point me to RATE data I would certainly be appreciative.
Thanks
Mark