proe2003
Mechanical
- Nov 16, 2003
- 3
I am using Ansys 7.0 to do a FEA on a torispherical head subjecting to internal pressure. According to my understanding, I should triger a nonlinear (material) analysis, especially at a thinner head thickness. I started at a thicker head thickness which limit the stress-strain relationship in the linear elastic zone on the stress-strain curve (engineering). I tried linear model (E=27.5 ksi) and nonlinear model (which has the same E=27.5 ksi for the linear region, and use several pionts to simulate the plastics zone). What I got is the different results from different models EVEN THOUGH the stress-strain relationship is in the linear zone. This really confused me! With the same E=27.5 ksi in linear zone of both models, why did I get different stress and strain values? The result from nonlinear model is considerable lower than that of linear model. For example:
for the same area as I am interested:
Linear model: strain range - 0.0007 to 0.001 stress: 19,000psi to 27,000psi
Nonlinear model: strain range - 0.0005 to 0.0007 stress: 13,000psi to 18,000psi
I have exact the same model setup for both models (meshing, boundary conditions,......).
The results fit the stress-strain cuver very well for both models. My question is why the results are quite different from different models with same E-27.5ksi in the linear elastic zone? I have checked that both models are using the same solver - Sparse Direct Solver.
Thank you for the help in advance!
Yi
for the same area as I am interested:
Linear model: strain range - 0.0007 to 0.001 stress: 19,000psi to 27,000psi
Nonlinear model: strain range - 0.0005 to 0.0007 stress: 13,000psi to 18,000psi
I have exact the same model setup for both models (meshing, boundary conditions,......).
The results fit the stress-strain cuver very well for both models. My question is why the results are quite different from different models with same E-27.5ksi in the linear elastic zone? I have checked that both models are using the same solver - Sparse Direct Solver.
Thank you for the help in advance!
Yi