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1
- #1
changedsoul
Computer
- Jul 9, 2010
- 24
A while back I was asking questions about calculating MOW from a given test radius. Thanks to "mfgenggear" I was able to put that into a nice TI89 calc prog that people at my shop use often. Now I am back wanting to add some more info to its output. I have hit a snag. Mostly because I am still learning about gears. Some Background. We have an old DOS program that spits some info out. Some of which I would like to duplicate to the TI calc. I can calculate everything this old DOS prog can with exception of a modified Gear I.D. or O.D.
Example: 23T, 20DP, 20PA. Modified C.T.T = .06526.
My calculation ( which is suspect ) for change in O.D. gives: 1.21351
The DOS program gives a value of 1.21757
And the Manufacturing Print actually calls out a O.D. of 1.219 +- .001.
So I'm trying to See which value is correct and what formula was used.
For mine I used the formula: C.T.T. = ( CP / 2 ) - ( 2 * O.D._Change * TAN(PA) ).
I Solved for the change in OD, Multiplied that by 2 and Subtracted that from the STD OD ( 1.25 ).
Am I on the right path? And I understand that the O.D. is not all the critical, but being math, I would like to know where there are three different answers for this.
Thanks.
Example: 23T, 20DP, 20PA. Modified C.T.T = .06526.
My calculation ( which is suspect ) for change in O.D. gives: 1.21351
The DOS program gives a value of 1.21757
And the Manufacturing Print actually calls out a O.D. of 1.219 +- .001.
So I'm trying to See which value is correct and what formula was used.
For mine I used the formula: C.T.T. = ( CP / 2 ) - ( 2 * O.D._Change * TAN(PA) ).
I Solved for the change in OD, Multiplied that by 2 and Subtracted that from the STD OD ( 1.25 ).
Am I on the right path? And I understand that the O.D. is not all the critical, but being math, I would like to know where there are three different answers for this.
Thanks.