Help Designing a BJT amplifier in emitter follower config.

I need to find out how to design an amp with 2 resistors forming a potnetial divider on the base another resistor in the bas and an emitter resister with a cap in parallel from the base. and an 8ohm speaker in series with the emitter resister. I only know the supply is 5v and have no clue how to get the resistor and capacitor values.
Please Help

 

[jbartos]

Suggestion: There are some good handbooks of electronic circuits: e.g.
One by Markus and some by TAB Publishers. Also, there may be more up-to-date handbooks on

http://www.amazon.com

or

http://www.barnesnoble.com

Else, there are also electronic circuit textbooks since this appears to be more on textbook side problem with many reasonably good solutions.

 

[Merlin1xx1]

well this is easier with a diagram but i'll see if i can explain it
okay your source(in this case 5V) is tied to your collector. now there is also a resistor that goes from the source to the base and one from the base to ground, thats your voltage divider. you'll have to check to see what level that needs to be to turn the BJT on, i'd set the DC voltage to be just below that. the AC voltage will also be applied to the base and it will actual turn the BJT on(NOTE: remember to use a cap in series with the AC signal to take out all DC voltage). now you also need to know your Max current draw, once you have that you can find how much current can be applied to the base so you'll know how to set input impedance. the capacitor off the collector will run in series with the output resistance, this is used to again filter out any DC voltage. on the emitter side you're again going to have a voltage drop...the BJT will probably drop .7V the rest will be dropped across the emitter so choose a resistor size accordingly...this is the basic layout of the circuit, since i don't know what you're doing i can't give you any cap/resistor values but theres a start.