Recent content by Neilmo

Hi, `Roark's Formulas for Stress & Strain` has a formula for buckling which takes account of the cylinder and rod inertias.

Hi there, Try `Youtube` and do a search for Solidworks animation tutorials. You will find no end of tutorials on all aspects of Solidworks. Regards, Ned

I think Zekeman is correct in that the scissor mechanism ensures that the table and load always remain parallel with the ground when being lifted, therefore the hydraulic cylinder can be assumed to be pinned at both ends because the scissor prevents the whole thing from falling over. There are...

Hi Galambos, Would this document be of any help to you. Regardshttp://files.engineering.com/getfile.aspx?folder=6e929759-6d36-4c9a-a027-d0fe79bf7e80&file=vibration.pdf

Simonmags, There is also this article which may be of interest to you - http://www.coachesinfo.com/index.php?option=com_content&view=article&id=10199:gymnastics-isbs-swinging&catid=183:mens-high-bar&Itemid=290 Read the first paragraph in the `Elastic Energy` section, which gives an indication...

Simonmags, Just found your posting, please take a look at the attached - hope it helps. Regardshttp://files.engineering.com/getfile.aspx?folder=5a5ef61d-61fa-4c20-ab7a-d55de1f85742&file=High_Bar_Load.pdf

waytsh There is a clause (which escapes me at present) somewhere in the British Standards, which states words to the effect that - you are not allowed `mutual dependency` of any restraint, there must be a positive connection to something solid. Your crane is effectively a mutual restraint to...

wsg1, Looking at BS5950-1:2000 under `column bases` section 4.13.1 it appears that `c` is a distance from the face of your column (pipe) to the edge of the baseplate. So I am not sure what `c` you are calculating. As dhengr points out - some more clarification is required! Neil

wsg1, Just to confirm IDS. I used a totally different approach to his method and came up with exactly the same figures. Neil

Hi wsg1, Generally speaking, no matter what set of random loads and spacings you have on a simply supported beam, the maximum deflection is always within a few percent of the mid-span. Using your figures, I calculate the maximum deflection to be 2.4217mm at a distance of 1651mm from the LH...

Hi wsg1, 1) Draw the bending moment diagram for your loaded beam (M) 2) Remove all of your loads and place a unit load (1.0 no units) at the point on your beam where you want to evaluate the deflection - say mid span 3) Draw a second bending moment diagram for this loading (m) 4) Multiply...

mizkn, Click the worksheet. In the File menu, click Page Setup, and then click the Sheet tab. Click print Gridlines. Regards, Neilmo

Hello Ian, Iskit4iam has hit the nail on the head, so to speak. He is quite correct in saying, that using a 1ph motor is down to current draw . If you are still using your existing 3ph supply to run a 1ph motor, then I would suggest to just use a 3kW 1ph motor and change nothing else...

Ian, Something here doesn't make sense to me - either you have a 2.5HP (1.85kW) motor, or a 3kW (4.0HP) motor, but not a 2.5HP (3kW) motor. Having said that, I don't know what `Casco` are talking about. Surely, if a 3kW 3ph (or whatever) motor will do the job now, then it can be replaced...

Aubrey, Bear in mind that, high strength steels are OK as long as `stress` is your design criteria and usually associated with `shorter` beams. If `deflection` is critical, usual on `longer` beams, then using a high strength steel will make no difference, as `E` (young's modulus of elasticity)...