billbusy
Mechanical
- Sep 29, 2011
- 75
I haven't took any courses about fluid mechanics before. Currently I have a question about compressor power & calculation of cooling discharge air.
The situation is like that:
For a one stage rotary compressor
Changes of state P2/P1 = (V1/V2)k = (T2/T1)k-1/k
Power P, kW {(k / k - 1)* P1*100000*Q1*[ (P2/P1)(k - 1/k) - 1 ]}/1000
Inlet Air is 20°C, 101 kPaa, 3700 m3/hr or 1.03 m3/s
Discharge Pressure is 790 kPaa
Per the adiabatic compression of air, the calculated results show: Discharge Temp is 256°C, the power of the compressor is 290 KW.
k P1, barA P2, barA T1, °C T1, K Q1, m3/s P, kW T2, K T2, °C
1.4 1 7.9 20 293.15 1.03 290.18 529.12 255.97
As there is a heat exchanger within the compressor kit to cool the discharge air to 20°C, I need to calculate how much cooling water is needed per hour. But interestingly, I found if I cool the air to 20°C, the absorbed power is:
Air density * air volume * Specific Heat of air * delta T == 1.2041 kg/m3 * 1.03 m3/s * 1.005 kJ/kg.K * 236K == 294 kJ/s ==294 kW
It is same as the power of the compressor....
I think I definitely have something wrong, as after cooling the discharge air to 20°C, the air pressure is still supposed to be 790 kPaa, the absorbed energy by the cooling water shouldn't be 294 kW.
Can anybody briefly told me where I am wrong in the 2nd part of the calculation and how to fix it? Thanks.
MSc. Mechanical Engineering;
4 years EPC experience;
Oil & Gas industry in Canada.
The situation is like that:
For a one stage rotary compressor
Changes of state P2/P1 = (V1/V2)k = (T2/T1)k-1/k
Power P, kW {(k / k - 1)* P1*100000*Q1*[ (P2/P1)(k - 1/k) - 1 ]}/1000
Inlet Air is 20°C, 101 kPaa, 3700 m3/hr or 1.03 m3/s
Discharge Pressure is 790 kPaa
Per the adiabatic compression of air, the calculated results show: Discharge Temp is 256°C, the power of the compressor is 290 KW.
k P1, barA P2, barA T1, °C T1, K Q1, m3/s P, kW T2, K T2, °C
1.4 1 7.9 20 293.15 1.03 290.18 529.12 255.97
As there is a heat exchanger within the compressor kit to cool the discharge air to 20°C, I need to calculate how much cooling water is needed per hour. But interestingly, I found if I cool the air to 20°C, the absorbed power is:
Air density * air volume * Specific Heat of air * delta T == 1.2041 kg/m3 * 1.03 m3/s * 1.005 kJ/kg.K * 236K == 294 kJ/s ==294 kW
It is same as the power of the compressor....
I think I definitely have something wrong, as after cooling the discharge air to 20°C, the air pressure is still supposed to be 790 kPaa, the absorbed energy by the cooling water shouldn't be 294 kW.
Can anybody briefly told me where I am wrong in the 2nd part of the calculation and how to fix it? Thanks.
MSc. Mechanical Engineering;
4 years EPC experience;
Oil & Gas industry in Canada.