kennyden
Electrical
- Jun 16, 2004
- 17
Hi,
I'm trying to calculate the service life for my battery powered application.
Here's how I calculate it. Please le me know if this the right way to do this.
I'm using 3X1.5 Volts AA type alkaline batteries -put in series- (energizer titanium e2) rated at "3135mAh (down to 0.8 volts)". My application works at 4.5 volts down to 2.6 volts.
So to get the total energy from the battery I multiplied 4.5V by 3135mA by 3600 (sec) which gives about 50787 joules.
I then took the total battery energy and divided it by my application's average power consumption per day at 4.5 volts, that is about 16 joules. So 50787/16.06 = 8.6 years !!
Now I know that theorically, 8.6 years is real long for 3XAA type alkaline batteries. I would surely need to caculate the energy derating over the years.
Nevertheless, I need about 4 years of battery life. Assuming the application is used at 23 degC ambient, will this do it ?
May I use the manufacturer rated energy this way ? Thanks for helping me. I'm no battery experts and my caculation results seem a bit unerealistic to me.
Thx
I'm trying to calculate the service life for my battery powered application.
Here's how I calculate it. Please le me know if this the right way to do this.
I'm using 3X1.5 Volts AA type alkaline batteries -put in series- (energizer titanium e2) rated at "3135mAh (down to 0.8 volts)". My application works at 4.5 volts down to 2.6 volts.
So to get the total energy from the battery I multiplied 4.5V by 3135mA by 3600 (sec) which gives about 50787 joules.
I then took the total battery energy and divided it by my application's average power consumption per day at 4.5 volts, that is about 16 joules. So 50787/16.06 = 8.6 years !!
Now I know that theorically, 8.6 years is real long for 3XAA type alkaline batteries. I would surely need to caculate the energy derating over the years.
Nevertheless, I need about 4 years of battery life. Assuming the application is used at 23 degC ambient, will this do it ?
May I use the manufacturer rated energy this way ? Thanks for helping me. I'm no battery experts and my caculation results seem a bit unerealistic to me.
Thx
