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conversion

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wd1980

Petroleum
Apr 9, 2019
47
Gents;
i have to convert from bar to mmH2O pressure of liquid (Condensate)?
i convert from bar to mmh2O then how to convert it to the specif liquid, should i multiply by the density??
Anyone to support

thx
 
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Divide by the relate density compared to water I. E. SG

Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
 
LittleInch
if i've understand, the mesured XX barg to the convertd YY mmH2O
then YYmmH2O/ (d liq/d Water)?

is it correct?

thx
 
Yes

Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
 
There are too many conversions in the life of a chemical engineer to remember arbitrarily which require dividing and which require multiplying. If you just know and understand the first principles it all becomes obvious.

The pressure at the base of a column of liquid is related to the height of the column by the relationship (in any consistent set of units):
Pressure = fluid density x acceleration of gravity x column height

In my memory banks this is stored as "P equals rho G H". This is much easier to remember than whether you need to multiply or divide. And far more useful.

For example, to convert from 5 bar to mm of a liquid with a density of 850 kg/m3 follow the following logic (assuming we are working in SI Units).
5 bar is equal to 500 000 Pascal. Acceleration of gravity is 9.81 m/s2. Column height is therefore
H = P / (rho x G) = 500 000 / (850 x 9.81) = 59.96 metre or 59 960 mm.

Katmar Software - AioFlo Pipe Hydraulics

"An undefined problem has an infinite number of solutions"
 
Thanks IRstuff [smile2] I've been involved in other projects for a couple of years and haven't had much time to devote here, but things are changing and I am wearing my engineering hat more often now.

Katmar Software - AioFlo Pipe Hydraulics

"An undefined problem has an infinite number of solutions"
 
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