API machines are mostly for Ex applications which are naturally costlier than generic IEC or IEEE machines.
Buy the standards and learn the differences.
Jeff
415 V, 25 KW, 50 A, 1500 RPM motor no load testing with VFD in our shop today
VFD input - 396 V, 6.66 A, 2.7 KW, 0.998 PF
VFD output - 415.8 V, 19.6 A, 1.2 KW
Hope it helps.
In the rotor DC circuit, the negative slipring will wear out faster than the positive one due to electrochemical reaction. So, to maintain even wear of both sliprings, the polarities are swapped. This has zero effect on the synch generator output / synch motor direction of rotor.
For the same...
Changing the polarity of rotor field winding has zero effect on the synch generator/motor output.
If you changed only the bearings, why do you need to test the generator without the prime mover?
https://tgadvisers.com/steam-turbine-and-generator-reduced-minimum-load-considerations/
If you got 20k, have at it.
https://www.epri.com/research/products/000000003002013589
"If I reduce the KVA that should equate to a reduction in amps, correct?"
Correct.
"if there is an amp reduction, shouldn't I be able to calculate an efficiency increase?"
The reduced current means less I^2R loss in the generator, cables, transformer, which is indeed a power saving. You need...
Littleinch
Yes, if the acceleration time is increased from 5 to 10 minutes for 0 to 3300 RPM, the power required drops to half i.e. 14.34 KW.
I am looking at a linear acceleration which the VFD will be programmed to do.
Both the drive cage induction motor and VFD are rated for 132 KW.
I...
Thanks, Greg.
I did do some math (had to recall some college days equations) and got exactly double of that i.e. 28.68 KW.
Wonder where I am going wrong.
Got moment inertia I = 72 kg-sq m right
Torque = Moment of inertia x Angular acceleration = 82.97 N-m
Power = torque x angular speed =...
What will be the power needed to rotate a uniform cylindrical rotor
weighing 1600 kgs
dia 600 mm
speed 3300 RPM
5 minutes acceleration time from zero speed to 3300 RPM
Any particular equation to calculate this? Will acceleration time play a role in power needed?
The cylindrical rotor will be...
In a given motor frame size, 2 to 4 speeds can be designed with corresponding power rating. You need to look for the same frame with the same speed and HP that you want.
No standards will specify the power and speed ratings for frame sizes.
"We are bit sure that the problem is in rotor laminations because a similar motor with the same symposium was deconstructed and found a deformation in it’s lamination."
What kind of deformation? Post some pictures and complete motor nameplate.