Recent content by fortjp500

Thanks that gets me close enough.

Thanks for that. Those interface angle equations are very useful. But in my case of the vertical aluminum extrusion interface angle ends up being 0.0007° which results in only .0002" of deflection from interface rotation and the 18" horizontal member rotating prior to it's own deflection. So I'm...

I'm not 100% on how to determine what that rotation of the interface will be. Can I just look at the inverse tangent of the vertical's deflection from the moment over the vertical's length to get an angle to apply to the horizontal?

I was not. I think that will likely be the factor I'm missing. Thanks.

Yeah I have both of those calculated but would you just add those together? The result of that is much less than what FEA is giving for displacement.

Here's some info if the details help.

Good morning, I'm struggling to find the theory of how to validate the deflection of two pieces of 8020 aluminum extrusion that are assumed to be fixed to each other and fixed to the ground. I think I'm going about it wrong, but when I calculate the static beam deflection of a point load applied...

Correct

Yes the sheet. There is only edge contact when the nut rotates on the edge of the sheet.

I saw this at work today. It's a .812 square nut (.413" deep/tall) in a slot that measures 0.875. The material is mild steel 1/4" thick. Calculating the shear from the clamp load is pretty straightforward. I'm wondering more about let's say the square nut and bolt threads are seized, and you...

I get that yield stress = E * y/ neutral axis. I don't understand what y is and how it relates to diametral deflection. For example if I am installing say a 1 inch radius rod into an eye that has an undersized inside radius of say 0.975" that would be diametral interference of 0.050". If the...

I would like to determine how big of a tapered solid rod of steel I could insert to open the eye up before the eye or rod would yield. I was hoping there was some theoretical answer to this that someone was familiar with.

I hadn't thought of it as a curved beam with a rectangular cross section but that would be the case for sure. If I know the inner diameter of the spring eye and the outer diameter of the bushing that will be interfering, is there a way to get to stress from there using the moment equation...

The formula shown would be useless as soon as one would make a cut in the outer housing as it would no longer be attached (like a leaf spring eye is). I want to calculate the mating surface pressure which I can then use to determine the stess in the outer member.