Great Thread.
Ask any software maker and they will tell you its absolutley necessary to have minor revisions and almost all have adopted it - from internet explorer I am viewing in his page 8.0.7600.16385
We have a number of geographical sites so pre-production, whilst designs are being...
Hi all,
We have a piece of moving machinery operated hydraulically which works in an area with limited space. I am having a problem designing the routing of a -24 (1 1/2") flexible tube because the minimum bend radius (around 500mm for 210 Bar rated hose).
If I were to split this -24 hose...
vzeos,
Unfortunately I don't have access to this particular book, but you are correct a 90 deg mitre is the closest description I have seen. The only reference to a loss factor k for this I can find is 1.1 from BS Massey.
Hi all,
Does anyone have any suggestions or know of published data on K factors for a machined hydraulic manifold block. What I am most interested in is a typical 90 degree bend (eg R/d = 0) created from boring into the block from different sides of block.
Also, does standard 'equivalent...
Hi All,
Have been toying around in my head for a day or so now a problem that can be simplified to that as shown here;
http://www.mytempdir.com/868898 (note - drawn in 3rd Angle) With a load at G.
My question is;
If I am to model this with fixed ends that support a moment Mz by placing a...
Found a kind of work around, create a new revision row, change the letter in the revision balloon to what it should be then delete it (if required). Now when adding a new row in the table it should.
Doesn't seem to update the embedded value though ie, the a note containing property linked to...
Hi all,
Making a drawing just now I accidently added a couple of rows too many in a revision table (SW standard table) and deleted them. Anyway now when I add a rev it wants to go from Rev B to Rev E.
Anyone know where I can reset this?
Dave
What welding standard are you using?
I would have thought the |\ symbol is correct for a bevel weld below the line (assuming the line is at the apex). If it was the other way round would you not have a fillet weld?
dw
Hi All,
I need to spec some components to price up and achieve the following; Get data from a Rotary encoder to a laptop for data gathering.
This will be a field device (picture someone setting up a stationary wheel that touches an oscillating plate) recording the linear motion via the...
Love this type of stuff, do you have a proof you can quickly post here Greg (Way off topic I know but...)
The example I found on the net was;
2x3 = 1 x 2 x 3 = 6
2^3 = 1 x 2 x 2 x 2 = 8
Therefore;
2^0 = 1
and 0^0 = 1
DW
I doubt COSMOS Express would be failing because of the memeber failing under buckling.
I would be very very wary of using Cosmos express in this way.
There are some very simple calculations available for buckling by (amongst others) a chap named Euler.
In its simplest form for pinned ends...
