Recent content by Chezma

Thank you.

Is the super conductor already available in the market in a wire form ? What that material is? What about the cost ?

Thanks pete,that is a perfect answer to my question. May i ask you where i can get a copy of the simulator software you have ?

Well,until now i have not get any clear answer,if the current contains ac and dc component,then to block the dc current component then we need a capacitor not resistor !

I am agree with you electricpete in the case of a resistor exists in circuit ,but what would be the behavior if no resistor is there, just only pure inductance.

electricpete,what is the transient response of a pure inductance to a square wave ? With no resistor included.

Yes,correct the square wave averages to zero - it is identical around the horizontal axis.

Let us explain this phenomena in different way: Suppose a voltage of train of square wave of pluses (with only positive polarity)applied to a pure inductance,and according to the equation: V = N.do/dt , whare o is the flux The flux wave form will start from zero and increases linearly to its...

That is ok,but at transient L has infinit impedance and at steady state has a finite impedance and not zero.

So,why for a steady state cyclic operation we need a resistive load with the pure inductance to get a vlid relation between current and voltage according to the equation: v = - L.di/dt ??? What is the secret in that resistor ???

Even the simulator doesn't work if pure inductance is connected across AC supply unless a resistor in series included.

The relation between voltage and current for an inductor is given by: v = L . di/dt I think this relation is valid only in steady state periodic cyclic operation and provided that the circuit contains a resistive element. My question now :Why a resistive element should be contained in the...

So,can you prove that the two above circuits are equivalent for step input and have the same time constant. 1)Circuit one: R1 in parallel with L1 and the combination in series with R2. 2)Circuit two: R3 in series with L2.

I simplified the device to a resistor R1 in parallel with inductor L1 and this combination in series with another resistor R2 ,the input is step funtion. But how this arrangement can be reduced furthe to one resistor in seires with one inductor ?

I think thevenin's theorem can be used in very special way for step input to simpify the circuit and end up with inductance an resistor in series.