Hi,
There's an important factor that is the yield stress factor epsilon, that will need to involve the yield strength of the steel. Then use that for classification of the cross section.
Below pictures is examples of the same tube size but one with S355 and one with S235, they are classified...
Hi,
I found a couple of reference recommend torque charts, the one below is simple to read (closest to M10 is 3/8 inch, torque converted to N.m is 22N.m):
https://l-36.com/torque.php
By the way, found this original topic from 2008 in below discussion...
Then torque at 5N.m seems good enough for this bolt (just a guess without knowing more detail the clamped parts & their working condition) [pipe]
Engineering is a journey of thousand miles begins with a single step
Hi, I think the most simple is check for stress of bolt under that torque / preload, and 40N.m seems a bit high for M10 brass bolt:
Engineering is a journey of thousand miles begins with a single step
Hi desertfox,
The joint in this example has value of load sharing ratio of 0.19, so bolt will feel 19% of external load in additional to preload as long as joint is not seperated.
Diagrams of test 4 (external 85 kN and 120 kN)with a scaled view for load case has external load 120 kN:
In...
Hi,
I made a few theoritically checks on excel for this case with hex.h bolt M16, grade 8.8 and 10.9, layout as below:
Test 1 with 10.9 and pretension 100% yield. Seperation is higher than ultimate, so bolt will break before seperation occurred, at an external force 85kN:
Test 2 with 10.9...
Hi,
In term of bolt strength according to EN 1993-1-8, table 3.4, the tension resistance of countersunk bolt is about 70% compared to the other head types (by comparing factor k2, 0.63 / 0.9 = 0.7)
Engineering is a journey of thousand miles begins with a single step
Good morning all,
I know this topic has been discussed around but all threads mostly locked. What I am confusing is Euler buckling check for a pinned-pinned connection of rod in fully extracted cylinder on chapter 3.7.4 is Peu = pi^2*E*I/(2*L^2), from other sources the formular is Peu =...
