Hello Group,
I have a frame 24,000 lbs hung over two jigs aproximately 400" apart. I am trying to analyse the job in ansys and the results I am getting are rediculous (I think). Please see the attached .pdf file to understand the problem better and results from ansys. As the jigs are equally...
rb1957:
I am sorry if the picture is not very clear and I thought I answered the posed question - I may not have clearly understood the question.
I am applying the load to the geometry. There are at least 8 nodes and 7 elements which take the load. I could refine the mesh and increase the...
SWComposites:
Yes, I have applied the load over 3/4" X 2" area. I have 10,000 lb force supported between two points. The current point is at 19.2" from the load, so it creates a load of 5614 lbs and a moment of 108080 lb-in. The other end is at 24.6" and is spread over large cross-section so I...
Hello All,
I am a rookie to FEA world. I am using ANSYS14 to perform stress calcualtion on a steel structure. This is static analysis.
I have a 3" thick 50 grade steel plate solidly welded to the tubular structure behind. It takes a concentrated load of 5614 lbs and a large moment. The analysis...
Hello group,
Does anyone know of any kind of viewer available out there where I can view the model, loading, mesh and results created in ANSYS workbench without actual ANSYS software installed?
[I usually perfrom FEA in ANSYS workbench and make report and submit to the customers but this one...
Thanks guys fot the prompt response.
@hydtools: Initillay I did not think it was a indeterminate problem and I thought I was missing something. It took sometime for me to understand the link you sent me and now I'll try solve my problems using those concepts. I am not soure I will succeed but...
Hello All,
I am trying to resolve a force in to four supports but could not do it. Its been a while I studied engineering statics, I guess I forgot the basics of it. I know its a very simple problem. I would really appreciate if any one can help solve this thing.
Thanx in advance.
Thank you guys for all the replies.
Electricpete:
"The KE at that point is reduced to KE_Remaining = KE-PE = 314460.1888 ft lbf"
What is the formula to convert this energy into force on the wall behind the rubber??? any help? I dont know how much time to assume for it to come to stop...
Thank you desertfox and electricpete.
I tried to solve the above equations provided by desertfox with my actual values...
Weight =100 kips ; therefore mass (m) = 100,000/32.2 = 3105.6 lb/ft/sec^2
velocity= 14.6 ft/sec
rubber stiffness k = 1200 kips/ft (very stiff rubber)
(rubber thickness is...
Hello All,
I am sure this question was asked in the forum before but I could not find it.
Please look at the attachement and help me figure out the force F on the wall behind rubebr, if a weight W travelling with a velocity V hits the wall reinforced with rubber (spring constant K).
FYI: I am...
